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Can anyone direct me to a website which explains how one might
calculate the orbits of the planets from observations in order to confirm that orbits are in fact ellipses rather than some other proposed shape? A general description would be more useful than the detailed mathematics, but both would be good. If no-one has a website, could you just give me an outline of what would be involved? I'm more interested in an easy way to do it with modern techniques than in how Kepler did it. -- Jeff, in Minneapolis Subtract 1 from my e-mail address above for my real address. .. |
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"Jeff Root" wrote in message
om... Can anyone direct me to a website which explains how one might calculate the orbits of the planets from observations in order to confirm that orbits are in fact ellipses rather than some other proposed shape? A general description would be more useful than the detailed mathematics, but both would be good. If no-one has a website, could you just give me an outline of what would be involved? I'm more interested in an easy way to do it with modern techniques than in how Kepler did it. -- Jeff, in Minneapolis How about starting with the Earth's orbit? We can see, by the progression of the constellations in the night sky through the year, that the Earth goes around the Sun (or vice versa, but let's not go down that route... assume we know that the Earth goes around the Sun). Make precise measurements of the size of the Sun's disk throughout the year and use the information to show that the orbit is elliptical -- we can derive the eccentricity and relative dimensions of the orbit from the disk size information. In particular, the data should fit an equation of the form: r = p/(1 + e*cos(q)) where r is the radius p is a scale parameter e is the eccentricity q is the true anomaly |
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Greg Neill replied to Jeff Root:
How about starting with the Earth's orbit? Exactly where I wanted to start! We can see, by the progression of the constellations in the night sky through the year, that the Earth goes around the Sun (or vice versa, but let's not go down that route... assume we know that the Earth goes around the Sun). Make precise measurements of the size of the Sun's disk throughout the year and use the information to show that the orbit is elliptical -- I thought of that. I don't know but can figure out on my own what the change in size should be, to determine how difficult it would be to measure. I wonder whether the change would be enough to produce useable values, given no access to the McMath Solar Telescope, or the like. we can derive the eccentricity and relative dimensions of the orbit from the disk size information. In particular, the data should fit an equation of the form: r = p/(1 + e*cos(q)) where r is the radius p is a scale parameter e is the eccentricity q is the true anomaly I wildly surmise that p would be the same for all observations if the setup used to make the measurements is unchanging, but I can't guess whether it would then become 1 or if the value needs to somehow be determined separately. The date of perihelion and length of the year would be easy enough to determine, but there are still unknowns on both sides of the equation: radius and eccentricity. I don't know what to do with the equation. And I need to go beyond Earth to determine the ellipticality of other planets' orbits, too. -- Jeff, in Minneapolis .. |
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"Jeff Root" wrote in message
m... Greg Neill replied to Jeff Root: Make precise measurements of the size of the Sun's disk throughout the year and use the information to show that the orbit is elliptical -- I thought of that. I don't know but can figure out on my own what the change in size should be, to determine how difficult it would be to measure. I wonder whether the change would be enough to produce useable values, given no access to the McMath Solar Telescope, or the like. we can derive the eccentricity and relative dimensions of the orbit from the disk size information. In particular, the data should fit an equation of the form: r = p/(1 + e*cos(q)) where r is the radius p is a scale parameter e is the eccentricity q is the true anomaly Okay. At perihelion q = 0, and at aphelion q = 180 degrees. So the perihelion and aphelion orbital radii a rp = p/(1 + e) = a(1 - e) a is the semimajor axis ra = p/(1 - e) = a(1 + e) If the diameter of the Sun is D and the distance is r then the angle subtended by the sun is (for small angles): w = D/r The ratio angles, perihelion to aphelion, is R = (D/rp)/(D/ra) = ra/rp = (1 + e)/(1 - e) For the Earth the eccentricity is about 0.0167 . So the ratio becomes: R = 1.034 That's about a 3.4% difference in size, which should be easily measurable on a projection of the Sun's image, which can be a couple of feet in diameter if desired. So working in reverse, from the measured ratio we can find the eccentricity. I wildly surmise that p would be the same for all observations if the setup used to make the measurements is unchanging, but I can't guess whether it would then become 1 or if the value needs to somehow be determined separately. Note that p dropped out of the equation for the eccentricity determination. The date of perihelion and length of the year would be easy enough to determine, but there are still unknowns on both sides of the equation: radius and eccentricity. I don't know what to do with the equation. And I need to go beyond Earth to determine the ellipticality of other planets' orbits, too. Once you've got the Earth's orbital shape pinned down (eccentricity and orientation), use its measure as the unit (i.e. astronomical unit AU) and determine the other orbits in terms of this scale. The value of p in the first equation is related to the eccentricity and semimajor axis by p = a(1 - e^2) So if a is set at 1AU, p for the Earth follows, and you've got an equation for the Earth's orbit: radius vs true anomaly. The true anomaly can be determined for a given moment by observing the constellation locations. Now you need to take all your observations of the planets, keeping in mind that you're working from a moving platform, the Earth. But you can now 'reduce' your observations thanks to knowing how your platform is moving. It becomes an exercise in geometry. It might be easiest to employ a modern orbit-fitting procedure like Herget's method for optical observations. |
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Jeff Root wrote:
Greg Neill replied to Jeff Root: How about starting with the Earth's orbit? Exactly where I wanted to start! We can see, by the progression of the constellations in the night sky through the year, that the Earth goes around the Sun (or vice versa, but let's not go down that route... assume we know that the Earth goes around the Sun). Make precise measurements of the size of the Sun's disk throughout the year and use the information to show that the orbit is elliptical -- I thought of that. I don't know but can figure out on my own what the change in size should be, to determine how difficult it would be to measure. I wonder whether the change would be enough to produce useable values, given no access to the McMath Solar Telescope, or the like. It's easy to see that the orbit cannot be a circle centered in the Sun. This was known to Jesuit astronomers using pinhole projection (on a really large and precise scale) within the generation after Galileo. In fact, they were able to show that the results fit Kepler's equal-area law rather than the sort of motion that the Ptolemaic system would induce with uniform but off-center circular motion. (See Heilbron's book _The Sun in the Church_). I still giggle at these poor scholastics deciding who got to tell the Pope. Bill Keel |
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